Integrand size = 31, antiderivative size = 263 \[ \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (1+x^2+x^4\right )^3} \, dx=\frac {e-2 g+(2 e-g) x^2}{12 \left (1+x^2+x^4\right )^2}+\frac {x \left (d+f-2 h-(d-2 f+h) x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {(2 e-g) \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )}+\frac {x \left (2 d+3 f-h-(7 d-7 f+4 h) x^2\right )}{24 \left (1+x^2+x^4\right )}-\frac {(13 d+2 f+h) \arctan \left (\frac {1-2 x}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {(13 d+2 f+h) \arctan \left (\frac {1+2 x}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {(2 e-g) \arctan \left (\frac {1+2 x^2}{\sqrt {3}}\right )}{3 \sqrt {3}}-\frac {1}{32} (9 d-4 f+3 h) \log \left (1-x+x^2\right )+\frac {1}{32} (9 d-4 f+3 h) \log \left (1+x+x^2\right ) \]
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Time = 0.18 (sec) , antiderivative size = 263, normalized size of antiderivative = 1.00, number of steps used = 17, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.355, Rules used = {1687, 1692, 1192, 1183, 648, 632, 210, 642, 1261, 652, 628} \[ \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (1+x^2+x^4\right )^3} \, dx=-\frac {\arctan \left (\frac {1-2 x}{\sqrt {3}}\right ) (13 d+2 f+h)}{48 \sqrt {3}}+\frac {\arctan \left (\frac {2 x+1}{\sqrt {3}}\right ) (13 d+2 f+h)}{48 \sqrt {3}}+\frac {\arctan \left (\frac {2 x^2+1}{\sqrt {3}}\right ) (2 e-g)}{3 \sqrt {3}}-\frac {1}{32} \log \left (x^2-x+1\right ) (9 d-4 f+3 h)+\frac {1}{32} \log \left (x^2+x+1\right ) (9 d-4 f+3 h)+\frac {x \left (-\left (x^2 (7 d-7 f+4 h)\right )+2 d+3 f-h\right )}{24 \left (x^4+x^2+1\right )}+\frac {x \left (-\left (x^2 (d-2 f+h)\right )+d+f-2 h\right )}{12 \left (x^4+x^2+1\right )^2}+\frac {\left (2 x^2+1\right ) (2 e-g)}{12 \left (x^4+x^2+1\right )}+\frac {x^2 (2 e-g)+e-2 g}{12 \left (x^4+x^2+1\right )^2} \]
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Rule 210
Rule 628
Rule 632
Rule 642
Rule 648
Rule 652
Rule 1183
Rule 1192
Rule 1261
Rule 1687
Rule 1692
Rubi steps \begin{align*} \text {integral}& = \int \frac {x \left (e+g x^2\right )}{\left (1+x^2+x^4\right )^3} \, dx+\int \frac {d+f x^2+h x^4}{\left (1+x^2+x^4\right )^3} \, dx \\ & = \frac {x \left (d+f-2 h-(d-2 f+h) x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {1}{12} \int \frac {11 d-f+2 h-5 (d-2 f+h) x^2}{\left (1+x^2+x^4\right )^2} \, dx+\frac {1}{2} \text {Subst}\left (\int \frac {e+g x}{\left (1+x+x^2\right )^3} \, dx,x,x^2\right ) \\ & = \frac {e-2 g+(2 e-g) x^2}{12 \left (1+x^2+x^4\right )^2}+\frac {x \left (d+f-2 h-(d-2 f+h) x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {x \left (2 d+3 f-h-(7 d-7 f+4 h) x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {1}{72} \int \frac {15 (4 d-f+h)-3 (7 d-7 f+4 h) x^2}{1+x^2+x^4} \, dx+\frac {1}{4} (2 e-g) \text {Subst}\left (\int \frac {1}{\left (1+x+x^2\right )^2} \, dx,x,x^2\right ) \\ & = \frac {e-2 g+(2 e-g) x^2}{12 \left (1+x^2+x^4\right )^2}+\frac {x \left (d+f-2 h-(d-2 f+h) x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {(2 e-g) \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )}+\frac {x \left (2 d+3 f-h-(7 d-7 f+4 h) x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {1}{144} \int \frac {15 (4 d-f+h)-(15 (4 d-f+h)+3 (7 d-7 f+4 h)) x}{1-x+x^2} \, dx+\frac {1}{144} \int \frac {15 (4 d-f+h)+(15 (4 d-f+h)+3 (7 d-7 f+4 h)) x}{1+x+x^2} \, dx+\frac {1}{6} (2 e-g) \text {Subst}\left (\int \frac {1}{1+x+x^2} \, dx,x,x^2\right ) \\ & = \frac {e-2 g+(2 e-g) x^2}{12 \left (1+x^2+x^4\right )^2}+\frac {x \left (d+f-2 h-(d-2 f+h) x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {(2 e-g) \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )}+\frac {x \left (2 d+3 f-h-(7 d-7 f+4 h) x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {1}{3} (-2 e+g) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+2 x^2\right )+\frac {1}{32} (-9 d+4 f-3 h) \int \frac {-1+2 x}{1-x+x^2} \, dx+\frac {1}{96} (13 d+2 f+h) \int \frac {1}{1-x+x^2} \, dx+\frac {1}{96} (13 d+2 f+h) \int \frac {1}{1+x+x^2} \, dx+\frac {1}{32} (9 d-4 f+3 h) \int \frac {1+2 x}{1+x+x^2} \, dx \\ & = \frac {e-2 g+(2 e-g) x^2}{12 \left (1+x^2+x^4\right )^2}+\frac {x \left (d+f-2 h-(d-2 f+h) x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {(2 e-g) \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )}+\frac {x \left (2 d+3 f-h-(7 d-7 f+4 h) x^2\right )}{24 \left (1+x^2+x^4\right )}+\frac {(2 e-g) \tan ^{-1}\left (\frac {1+2 x^2}{\sqrt {3}}\right )}{3 \sqrt {3}}-\frac {1}{32} (9 d-4 f+3 h) \log \left (1-x+x^2\right )+\frac {1}{32} (9 d-4 f+3 h) \log \left (1+x+x^2\right )+\frac {1}{48} (-13 d-2 f-h) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,-1+2 x\right )+\frac {1}{48} (-13 d-2 f-h) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+2 x\right ) \\ & = \frac {e-2 g+(2 e-g) x^2}{12 \left (1+x^2+x^4\right )^2}+\frac {x \left (d+f-2 h-(d-2 f+h) x^2\right )}{12 \left (1+x^2+x^4\right )^2}+\frac {(2 e-g) \left (1+2 x^2\right )}{12 \left (1+x^2+x^4\right )}+\frac {x \left (2 d+3 f-h-(7 d-7 f+4 h) x^2\right )}{24 \left (1+x^2+x^4\right )}-\frac {(13 d+2 f+h) \tan ^{-1}\left (\frac {1-2 x}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {(13 d+2 f+h) \tan ^{-1}\left (\frac {1+2 x}{\sqrt {3}}\right )}{48 \sqrt {3}}+\frac {(2 e-g) \tan ^{-1}\left (\frac {1+2 x^2}{\sqrt {3}}\right )}{3 \sqrt {3}}-\frac {1}{32} (9 d-4 f+3 h) \log \left (1-x+x^2\right )+\frac {1}{32} (9 d-4 f+3 h) \log \left (1+x+x^2\right ) \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.57 (sec) , antiderivative size = 303, normalized size of antiderivative = 1.15 \[ \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (1+x^2+x^4\right )^3} \, dx=\frac {1}{144} \left (-\frac {6 \left (-4 e \left (1+2 x^2\right )+g \left (2+4 x^2\right )+x \left (-2 d-3 f+h+7 d x^2-7 f x^2+4 h x^2\right )\right )}{1+x^2+x^4}+\frac {12 \left (e+2 e x^2-g \left (2+x^2\right )+x \left (d+f-d x^2+2 f x^2-h \left (2+x^2\right )\right )\right )}{\left (1+x^2+x^4\right )^2}-\frac {\left (\left (-47 i+7 \sqrt {3}\right ) d+\left (17 i-7 \sqrt {3}\right ) f+2 \left (-7 i+2 \sqrt {3}\right ) h\right ) \arctan \left (\frac {1}{2} \left (-i+\sqrt {3}\right ) x\right )}{\sqrt {\frac {1}{6} \left (1+i \sqrt {3}\right )}}-\frac {\left (\left (47 i+7 \sqrt {3}\right ) d-\left (17 i+7 \sqrt {3}\right ) f+2 \left (7 i+2 \sqrt {3}\right ) h\right ) \arctan \left (\frac {1}{2} \left (i+\sqrt {3}\right ) x\right )}{\sqrt {\frac {1}{6} \left (1-i \sqrt {3}\right )}}-16 \sqrt {3} (2 e-g) \arctan \left (\frac {\sqrt {3}}{1+2 x^2}\right )\right ) \]
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Time = 0.43 (sec) , antiderivative size = 262, normalized size of antiderivative = 1.00
method | result | size |
default | \(-\frac {\left (\frac {7 d}{3}-\frac {7 f}{3}+\frac {4 h}{3}-\frac {4 e}{3}-\frac {g}{3}\right ) x^{3}+\left (-6 d +4 f -2 h +2 g \right ) x^{2}+\left (\frac {20 d}{3}-\frac {13 f}{3}+\frac {5 h}{3}+\frac {e}{3}-\frac {8 g}{3}\right ) x -4 d +\frac {4 f}{3}-2 e +2 g}{16 \left (x^{2}-x +1\right )^{2}}-\frac {\left (27 d -12 f +9 h \right ) \ln \left (x^{2}-x +1\right )}{96}-\frac {\left (-\frac {13 d}{2}-16 e -f +8 g -\frac {h}{2}\right ) \sqrt {3}\, \arctan \left (\frac {\left (2 x -1\right ) \sqrt {3}}{3}\right )}{72}+\frac {\left (-\frac {7 d}{3}+\frac {7 f}{3}-\frac {4 h}{3}-\frac {4 e}{3}-\frac {g}{3}\right ) x^{3}+\left (-6 d +4 f -2 h -2 g \right ) x^{2}+\left (-\frac {20 d}{3}+\frac {13 f}{3}-\frac {5 h}{3}+\frac {e}{3}-\frac {8 g}{3}\right ) x -4 d +\frac {4 f}{3}+2 e -2 g}{16 \left (x^{2}+x +1\right )^{2}}+\frac {\left (27 d -12 f +9 h \right ) \ln \left (x^{2}+x +1\right )}{96}+\frac {\left (\frac {13 d}{2}-16 e +f +8 g +\frac {h}{2}\right ) \arctan \left (\frac {\left (1+2 x \right ) \sqrt {3}}{3}\right ) \sqrt {3}}{72}\) | \(262\) |
risch | \(\text {Expression too large to display}\) | \(169779\) |
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Leaf count of result is larger than twice the leaf count of optimal. 485 vs. \(2 (236) = 472\).
Time = 1.22 (sec) , antiderivative size = 485, normalized size of antiderivative = 1.84 \[ \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (1+x^2+x^4\right )^3} \, dx=-\frac {12 \, {\left (7 \, d - 7 \, f + 4 \, h\right )} x^{7} - 48 \, {\left (2 \, e - g\right )} x^{6} + 60 \, {\left (d - 2 \, f + h\right )} x^{5} - 72 \, {\left (2 \, e - g\right )} x^{4} + 84 \, {\left (d - 2 \, f + h\right )} x^{3} - 96 \, {\left (2 \, e - g\right )} x^{2} - 2 \, \sqrt {3} {\left ({\left (13 \, d - 32 \, e + 2 \, f + 16 \, g + h\right )} x^{8} + 2 \, {\left (13 \, d - 32 \, e + 2 \, f + 16 \, g + h\right )} x^{6} + 3 \, {\left (13 \, d - 32 \, e + 2 \, f + 16 \, g + h\right )} x^{4} + 2 \, {\left (13 \, d - 32 \, e + 2 \, f + 16 \, g + h\right )} x^{2} + 13 \, d - 32 \, e + 2 \, f + 16 \, g + h\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x + 1\right )}\right ) - 2 \, \sqrt {3} {\left ({\left (13 \, d + 32 \, e + 2 \, f - 16 \, g + h\right )} x^{8} + 2 \, {\left (13 \, d + 32 \, e + 2 \, f - 16 \, g + h\right )} x^{6} + 3 \, {\left (13 \, d + 32 \, e + 2 \, f - 16 \, g + h\right )} x^{4} + 2 \, {\left (13 \, d + 32 \, e + 2 \, f - 16 \, g + h\right )} x^{2} + 13 \, d + 32 \, e + 2 \, f - 16 \, g + h\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x - 1\right )}\right ) - 12 \, {\left (4 \, d + 5 \, f - 5 \, h\right )} x - 9 \, {\left ({\left (9 \, d - 4 \, f + 3 \, h\right )} x^{8} + 2 \, {\left (9 \, d - 4 \, f + 3 \, h\right )} x^{6} + 3 \, {\left (9 \, d - 4 \, f + 3 \, h\right )} x^{4} + 2 \, {\left (9 \, d - 4 \, f + 3 \, h\right )} x^{2} + 9 \, d - 4 \, f + 3 \, h\right )} \log \left (x^{2} + x + 1\right ) + 9 \, {\left ({\left (9 \, d - 4 \, f + 3 \, h\right )} x^{8} + 2 \, {\left (9 \, d - 4 \, f + 3 \, h\right )} x^{6} + 3 \, {\left (9 \, d - 4 \, f + 3 \, h\right )} x^{4} + 2 \, {\left (9 \, d - 4 \, f + 3 \, h\right )} x^{2} + 9 \, d - 4 \, f + 3 \, h\right )} \log \left (x^{2} - x + 1\right ) - 72 \, e + 72 \, g}{288 \, {\left (x^{8} + 2 \, x^{6} + 3 \, x^{4} + 2 \, x^{2} + 1\right )}} \]
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Timed out. \[ \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (1+x^2+x^4\right )^3} \, dx=\text {Timed out} \]
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Time = 0.28 (sec) , antiderivative size = 217, normalized size of antiderivative = 0.83 \[ \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (1+x^2+x^4\right )^3} \, dx=\frac {1}{144} \, \sqrt {3} {\left (13 \, d - 32 \, e + 2 \, f + 16 \, g + h\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x + 1\right )}\right ) + \frac {1}{144} \, \sqrt {3} {\left (13 \, d + 32 \, e + 2 \, f - 16 \, g + h\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x - 1\right )}\right ) + \frac {1}{32} \, {\left (9 \, d - 4 \, f + 3 \, h\right )} \log \left (x^{2} + x + 1\right ) - \frac {1}{32} \, {\left (9 \, d - 4 \, f + 3 \, h\right )} \log \left (x^{2} - x + 1\right ) - \frac {{\left (7 \, d - 7 \, f + 4 \, h\right )} x^{7} - 4 \, {\left (2 \, e - g\right )} x^{6} + 5 \, {\left (d - 2 \, f + h\right )} x^{5} - 6 \, {\left (2 \, e - g\right )} x^{4} + 7 \, {\left (d - 2 \, f + h\right )} x^{3} - 8 \, {\left (2 \, e - g\right )} x^{2} - {\left (4 \, d + 5 \, f - 5 \, h\right )} x - 6 \, e + 6 \, g}{24 \, {\left (x^{8} + 2 \, x^{6} + 3 \, x^{4} + 2 \, x^{2} + 1\right )}} \]
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Time = 0.31 (sec) , antiderivative size = 222, normalized size of antiderivative = 0.84 \[ \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (1+x^2+x^4\right )^3} \, dx=\frac {1}{144} \, \sqrt {3} {\left (13 \, d - 32 \, e + 2 \, f + 16 \, g + h\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x + 1\right )}\right ) + \frac {1}{144} \, \sqrt {3} {\left (13 \, d + 32 \, e + 2 \, f - 16 \, g + h\right )} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x - 1\right )}\right ) + \frac {1}{32} \, {\left (9 \, d - 4 \, f + 3 \, h\right )} \log \left (x^{2} + x + 1\right ) - \frac {1}{32} \, {\left (9 \, d - 4 \, f + 3 \, h\right )} \log \left (x^{2} - x + 1\right ) - \frac {7 \, d x^{7} - 7 \, f x^{7} + 4 \, h x^{7} - 8 \, e x^{6} + 4 \, g x^{6} + 5 \, d x^{5} - 10 \, f x^{5} + 5 \, h x^{5} - 12 \, e x^{4} + 6 \, g x^{4} + 7 \, d x^{3} - 14 \, f x^{3} + 7 \, h x^{3} - 16 \, e x^{2} + 8 \, g x^{2} - 4 \, d x - 5 \, f x + 5 \, h x - 6 \, e + 6 \, g}{24 \, {\left (x^{4} + x^{2} + 1\right )}^{2}} \]
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Time = 3.44 (sec) , antiderivative size = 1611, normalized size of antiderivative = 6.13 \[ \int \frac {d+e x+f x^2+g x^3+h x^4}{\left (1+x^2+x^4\right )^3} \, dx=\text {Too large to display} \]
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